tolong dijawab dari no. 1-25!! please pake cara!

1)
A = { 2, 3, 5, 7, 11, 13 }
B = { 3, 5, 7, 9, 11, 13 }
A ∩  B = { 3, 5, 7, 11, 13 }

3)
[tex] {2}^{4} = 16[/tex]

11)
4(3x - 3)
= 12x - 12

12)
5xy + 5yz + z + 3xy - 2yz + 10z
= (5xy + 3xy) + (5yz - 2yz) + (z + 10z)
= 8xy + 3xy + 11z

13)
3(p - 2) - 5p + 6
= 3p - 6 - 5p + 6
= (3p - 5p) + (-6 + 6)
= -2p

14)
[tex](a - b)^{2} \\ = {a}^{2} - 2ab + {b}^{2} [/tex]

15)
[tex] (3b - 2)^{2} - (b - 3)^{2} \\ = 9b^{2} - 12b + 4 - ({b}^{2} - 6b + 9) \\ = 9b^{2} - 12b + 4 - {b}^{2} + 6b - 9 \\ = 8 {b}^{2} - 6b - 5[/tex]

16)
[tex]6 \times (3q) \times 4pq \times p \\ = 6 \times 3q \times 4pqp \\ = 72 {p}^{2} {q}^{2} [/tex]

17)
[tex](5 - 4y)(5 + 4y) \\ = {5}^{2} - (4y) ^{2} \\ = 25 - 16 {y}^{2} [/tex]

18)
3(3x + 5) - 5(7x - 3) = x + 7
9x + 15 - 35x + 15 = x + 7
-26x + 30 = x + 7
-26x - x = 7 - 30
-27 = -23[tex]x = \frac{23}{27} [/tex]

19)
[tex] \frac{3}{4} x - \frac{1}{5} = 3 \frac{1}{4} \\ \frac{3}{4} x - \frac{1}{5} = \frac{13}{4} \\ 15x - 4 = 65 \\ 15x = 65 + 4 \\ 15x = 69 \\ x = \frac{69}{15} \\ x = \frac{23}{5} \\ x = 4 \frac{3}{5} [/tex]

20)
[tex] \frac{1}{2} (3x - 6) = \frac{2}{3} (2x - 3) \\ 3x - 6 = 2 \times \frac{2}{3} (2x - 3) \\ 3x - 6 = \frac{4}{3} (2x - 3) \\ 3x - 6 = \frac{8}{ 3} x - 4 \\ 9x - 18 = 8x - 12 \\ 9x - 8x = - 12 + 18 \\ x = 6[/tex]

21)
[tex] \frac{1}{4} (x - 2) = \frac{1}{2} (x - 1) + \frac{1}{4} (x - 1) \\ x - 2 = 2(x - 1) + x - 1 \\ - 2 = 2x - 2 - 1 \\ 0 = 2x - 1 \\ - 2x = - 1 \\ x = \frac{1}{2} [/tex]

22)
[tex] \frac{6 + 2x}{2} = \frac{4x - 3}{5} \\ \frac{2(3 + x)}{2} = \frac{4x - 3}{5} \\ 3 + x = \frac{4x - 3}{5} \\ 15 + 5x = 4x - 3 \\ 5x - 4x = - 3 - 15 \\ x = - 18[/tex]

25)
5x + 18 = 6 + 2x
5x - 2x = 6 - 18
3x = -12 (bagi kedua sisi dengan 3)
x = -4