1.tentukan nilai x dari persamaan logaritma a.)3log(3x-4) = 3log(x+16) b.)2log(x-1)+2log(x-1)=3 c.)4log (x2-4x+5) = 4log(6x-11)

a. 3x-4 = x+16
3x-x = 16+4
2x = 20
x=20/2
x=10

b. x-1 + x-1 = 3
2x - 2 = 3
2x = 3+2
x = 5/2

c. 2x-4x+5 = 6x-11
-2x+5 = 6x-11
-2x-6x = -11-5
-8x = -16
x = -16/-8
x = 2