Tolong di bantu, pleaseeeee. Perlu besok dan belum siap

jawab

∫²₁ (x³ - 1/x³) dx + ₂⁵∫ (x³ - 1/x³) dx =

= ₁⁵ ∫ (x³ - x⁻³) dx

= [ 1/4 x⁴ + 1/2 x⁻²]⁵₁

= 1/4 (x⁴) + 1/2 (1/x²) ]⁵₁

= 1/4 (5⁴ -1⁴) + 1/2 { 1/25 - 1/1}

= 1/4 (624)  + 1/2 (- 24/25)

= 156  - 12/25

= 155 ¹³/₂₅


(5)
 
∫ 3x (2x² - 1)² dx
u = 2x² - 1
du = 4x dx
3x dx = 3/4 du

∫  3/4 u² du  =
= 3/4 . 1/3 . u³ + c
= 1/4  (2x² -1)³ + c

Caranya di gambar yaa