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Matematika
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Pertanyaan
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1 Jawaban
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1. Jawaban algebralover
Bangun ruang #1 : Setengah Bola
Volume Volume Setengah Bola = [tex] \frac{1}{2} [/tex] × Volume Bola
[tex] \pi = \frac{22}{7} [/tex]
r = 7
[tex]V = \frac{1}{2}. \frac{4}{3}. \pi . r^{3} [/tex]
[tex]V = \frac{1}{2}. \frac{4}{3}. \frac{22}{7}. 7^{3} [/tex]
[tex]V = \frac{1}{2}. \frac{4}{3}. \frac{22}{7}.49.7 [/tex]
[tex]V = \frac{2}{3}.22.49 [/tex]
[tex]V = \frac{2.22.49}{3} = \frac{2156}{3} [/tex]
[tex]V = 718 \frac{2}{3} [/tex] [tex] cm^{3} [/tex]
Bangun Ruang #2 : Kerucut
Volume Kerucut = [tex] \frac{1}{3}[/tex] × Luas Alas × Tinggi
Tinggi = 10 cm
[tex] \pi = \frac{22}{7} [/tex]
r = 7 cm
[tex]Luas Alas = \pi . r^{2} [/tex]
[tex]Luas Alas = \frac{22}{7}. 7^{2} [/tex]
[tex]Luas Alas = [/tex]22 × 7
[tex]Luas Alas = [/tex]154 cm²
Volume Kerucut = [tex] \frac{1}{3}[/tex] × Luas Alas × Tinggi
Volume Kerucut = [tex] \frac{1}{3}[/tex] × 154 × 10
Volume Kerucut = [tex] \frac{1}{3}[/tex] × 1.540
[tex]Volume Kerucut = 513 \frac{1}{3} [/tex] [tex] cm^{3} [/tex]
Volume Bangun = Volume Bangun Ruang #1 + Volume Bangun Ruang #2
Volume Bangun = [tex]718 \frac{2}{3} + 513 \frac{1}{3} [/tex]
Volume Bangun = [tex]718 + \frac{1}{3} + 513 + \frac{2}{3} [/tex]
Volume Bangun = [tex](718 + 513) + ( \frac{1}{3} + \frac{2}{3} )[/tex]
Volume Bangun = 1.231 + 1
Volume Bangun = 1.232 cm³