tolong dijawab ya kak nomor 27 :v

Mapel : Matematika
Bab : Persamaan Garisn

2x - y + 6 = 0
m = -a/b
    = -2/-1
    = 2

m1 x m2 = -1
   2 x m2 = -1
         m2 = -1/2

 y - y1 = m ( x - x1 )
 y - 1   = -1/2 ( x - 1 )
   y - 1 = -1/2x + 1/2
 2y - 2 = -x + 1
2y + x = 1 + 2
x + 2y = 3

2x - y + 6 = 0
-y = - 2x - 6
y = 2x + 6......... m = 2


Persamaan garis yang melewati titik (1,1) yang tegak lurus dengan y = 2x + 6
m₁.m₂ = - 1
m₁.2 = - 1
m₁ = - ¹/₂
x₁ = 1; y₁ = 1

y - y₁ = m₁ (x - x₁)
y - 1 = (-¹/₂)(x - 1)
y - 1 = -¹/₂ x + ¹/₂
y = -¹/₂ x + ¹/₂ + 1
y = -¹/₂ x + ³/₂ ........... semua ruas dikalikan 2
2y = 3 - x
x + 2y = 3 ................ Jawaban (a)