8log m+8log 1/6 = 2/3 maka m=

Kelas 10 Matematika
Bab Akar, Pangkat dan Logaritma

^ = pangkat

⁸log m + ⁸log (1/6) = 2/3
⁸log (m . 1/6) = 2/3
m/6 = 8^(2/3)
m/6 = (2³)^(2/3)
m = 2² . 6
m = 4 . 6
m = 24