no 2 sama 3 aja ka tolong y

[tex]2.\\s=vo.t+ \frac{1}{2}.a.t^2 \\ s=6.4+ \frac{1}{2}.3.4^2 \\ s=24+24\\ s=48m[/tex]
Menempuh jarak 48m
berakhir di titik Q=P+48
titik Q=24+48=72

3. Vo = 0
    Vt = 144km/jam = 40m/s
      t = 6 sekon
ditanya jarak?

[tex]vt = vo+a.t\\ 40=0+a.6\\ a= \frac{40}{6} =\frac{20}{3}m/s^2\\\\ s = vo.t+ \frac{1}{2}.a.t^2\\ s=0+ \frac{1}{2}. \frac{20}{3}.(6)^2\\ s=120m [/tex]