alar kuadrat persamaan x² -6x+8=10

[tex] {x}^{2} - 6x + 8 = 10 \\ {x}^{2} - 6x - 2[/tex]
gunakan rumus abc:
[tex]x \frac{}{1.2} = \frac{ - b + - \sqrt{ {b}^{2} + 4ac} }{2a} [/tex]
[tex]a = 1 \\ b = - 6 \\ c = - 2 \\ \sqrt{ {b}^{2} - 4ac } = \sqrt{( { - 6})^{2} - 4(1 )( - 2)} = 6.63 \\ x \frac{}{1} = \frac{ - ( - 6) + 6.63}{2} = 6.31 \\ x \frac{}{2} = \frac{ - ( - 6) - 6.63}{2} = - 0.3125[/tex]