ds/dt=3t²+4t-1 dan s (2)=5 maka... A. s=t³+2t²-t-11 B. s=t³+2t²-t-10 C. s=t³+2t²-t-9 D. s=t³+t²-t-11 E. s=t³+t²-t-9
Matematika
Zadawiah
Pertanyaan
ds/dt=3t²+4t-1 dan s (2)=5 maka...
A. s=t³+2t²-t-11
B. s=t³+2t²-t-10
C. s=t³+2t²-t-9
D. s=t³+t²-t-11
E. s=t³+t²-t-9
A. s=t³+2t²-t-11
B. s=t³+2t²-t-10
C. s=t³+2t²-t-9
D. s=t³+t²-t-11
E. s=t³+t²-t-9
1 Jawaban
-
1. Jawaban MchFaizal
s = integral ds/dt
[tex]s= \int\limits^a_b {(3t^2+4t-1)} \, dt\\ s=t^3+2t^2-t+C\\ s(2)=5 \\ 2^3+2(2)^2-2+C=5\\ 8+8-2+C=5\\ C=-9\\ s=t^3+2t^2-t-9 (C)[/tex]