Matematika

Pertanyaan

Tolong dibantu nomer 18 dan 19, Terimakasih
Tolong dibantu nomer 18 dan 19, Terimakasih

2 Jawaban

  • 18.
    1 = 3,14 x 6cm x 6cm x 5cm = 565,2cm3
    2 = 3,14 x 3cm x 3cm x 12cm = 339,12cm3
    3 = 3,14 x 3cm x 3cm x 8cm : 3 = 75,36cm3
    Total = 565,2cm3 + 339,12cm3 + 75,36cm3 = 979,68cm3

    19.
    1 = 22/7 x 0,7cm x 0,7cm x 5cm = 7,7cm3
    2 = 22/7 x 0,7cm x 0,7cm x 2,4cm : 3 = 1232cm3
    Total = 7,7cm3 + 1232cm3 = 1239,7cm3

    Maaf kl salah dmg agak ribet angkanya...
  • Mapel : Matematika.
    Kelas : 6 SD.
    Materi : Bangun Ruang Gabungan.

    Saya jawab yaa

    18. r = 12 ÷ 2
    = 6 cm
    V. Tabung bawah = πr² × t
    = 3,14 × 6² × 5
    = 3,14 × 36 × 5
    = 113,04 × 5
    = 565,2 cm³
    V. Tabung tengah = 3,14 × 3² × 12
    = 3,14 × 9 × 12
    = 28,26 × 12
    = 339,12 cm³
    V. Kerucut = ⅓ π r²
    = ⅓ × 3,14 × 3² × 8
    = ⅓ × 3,14 × 9 × 8
    = ⅓ × 3,14 × 9 × 8
    = 3,14 × 3 × 8
    = 9,42 × 8
    = 75,36 cm³
    V. keseluruhan = 525,2 + 339,12 + 75,36
    = 979,68 cm³ (d)

    19. r = 1,4 ÷ 2
    = 0,7 cm
    V. Tabung = 22/7 × 0,7² × 5
    = 22/7 × 0,49 × 5
    = 22 × 0,7 × 5
    = 15,4 × 5
    = 77 cm³
    V. Kerucut = ⅓ × 3,14 × 0,7² × 2,4
    = ⅓ × 3,14 ×0,49 × 2,4
    = 3.69264 ÷ 3
    = 1.23088
    V. keseluruhan = 77 + 1.23088
    = 78.23088 cm³ (Pilih aja jawaban terdekat) jawaban : b