Tentukan HP dari PS nilai mutlak [3x + 2]=[x - 1]

[tex] |3x + 2| = |x - 1 | \\ {(3x + 2)}^{2} = {(x - 1)}^{2} \\ 9 {x}^{2} + 12x + 4 = {x}^{2} - 2x + 1 \\ 8 {x}^{2} + 14x + 3 = 0 \\ (4x + 1)(2x + 3) = 0 \\ x = - \frac{1}{4} atau \: x = - \frac{3}{2} [/tex]