(√2-√3) / (√2+√3)=a+b√6; a dan b bilangan bulat,maka a+b= A. -5 B. -3 C. -2 D. 2 E. 3

Kelas 9 Matematika
Bab Akar dan Pangkat

(√2 - √3)/(√2 + √3)
= ((√2 - √3)/(√2 + √3)) . ((√2 - √3)/(√2 - √3))
= (√2² - √6 - √6 - √3²) / (√2² - √3²)
= (2 - 2√6 - 3)/(2 - 3)
= (-1 - 2√6)/(-1)
= 1 + 2√6

a + b√6 = 1 + 2√6

a = 1 dan b = 2

a + b = 1 + 2
a + b = 3

✩✩ E ✩✩

(√2 - √3) / (√2 + √3) = a + b √6

(√2 - √3) / (√2 + √3) × (√2 - √3) / (√2 - √3) = a + b √6
(2 - 2√6 + 3) / (2 - 3) = a + b √6
(-1 - 2√6) / -1 = a + b √6
1 + 2√6 = a + b √6
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jadi, dapt diketahui bahwa a = 1 dan b = 2....

maka=>

a + b =
1 + 2 =
3