Matematika

Pertanyaan

Diket a(-6,4) dan p(3,-1) bayangan titik a dilatasi (p,2)

1 Jawaban

  • a(-6, 4) Dilatasi [(3, -1), 2] a' (x', y')

    [tex] \binom{ {x}^{l} }{ {y}^{l} } = k \binom{x - p}{y - q} + \binom{p}{q} [/tex]

    [tex] \binom{ {x}^{l} }{ {y}^{l} } = \binom{3 \: \: \: \: \: \: \: 0}{0 \: \: \: \: \: \: \: \: 3} \binom{ - 6 - 3}{4 + 1} + \binom{3}{ - 1} \\ \binom{ {x}^{l} }{ {y}^{l} } = \binom{3 \: \: \: \: \: \: \: \: 0}{0 \: \: \: \: \: \: \: 3} \binom{ - 9}{5} + \binom{3}{ - 1} \\ \: \binom{ {x}^{l} }{ {y}^{l} } = \binom{ - 27}{15} + \binom{3}{ - 1} \\ \binom{ {x}^{l} }{ {y}^{l} } = \binom{ - 24}{14} [/tex]

    maka bayangan titik A'(-24, 14)

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