Matematika

Pertanyaan

1. Diketahui: f(x)=2x^2 +5x+ 2 dan g(x) = 2x^2 -x-1 Tentukan : a) (f+g)(x). E) (f+g)(0) B) (f-g)(x). F) (f-g)(3) C) (f.g) (x). G) (f.g)(-1) D) (f/g)(x). H) (f/g)(2)

1 Jawaban

  • a)(f+g)(x)=f(x)+g(x)
    =(2x²+5x+2)+(2x²-x-1)
    =4x²+4x+1
    e)(f+g)(0)=4(0)²+4(0)+1
    =1
    b)(f-g)(x)=f(x)-g(x)
    = (2x²+5x+2)-(2x²-x-1)
    =2x²+5x+2-2x²+x+1
    =6x+3
    f)(f-g)(3)=6(3)+3
    =21
    c)(f.g)(x)=(2x²+5x+2)(2x²-x-1)
    =4x⁴-2x³-2x²+10x³-5x²-5x+4x¹-2x-2
    =4x⁴+8x³-3x²-7x-2
    g)(f.g)(-1)=4(-1)⁴+8(-1)³-3(-1)²-7(-1)-2
    =4-8+3+7-2
    =4
    d)(f/g)(x)=2x²+5x+2/2x²-x-1
    =5x+2/-x-1
    h)(f/g)(2)=5(2)+2/-2-1
    =12/-3
    =-4

Pertanyaan Lainnya