tolong buat caranya no 3 yang b dan c

[tex]b. \\ \sqrt[3]{128} = 4 \sqrt[3]{2} \\ \sqrt[3]{64 \times 2} = 4 \sqrt[3]{2} \\ \sqrt[3]{ {4}^{3} \times 2 } = 4 \sqrt[3]{2} \\ 4 \sqrt[3]{2} = 4 \sqrt[3]{2} \\ \\ c. \\ \sqrt[4]{243} = 3 \sqrt[4]{3} \\ \sqrt[4]{81 \times 3} = 3 \sqrt[4]{3} \\ \sqrt[4]{ {3}^{4} \times 3} = 3 \sqrt[4]{3} \\ 3 \sqrt[4]{3} = 3 \sqrt[4]{3} [/tex]