Matematika

Pertanyaan

1.tentukan persamaan garis yang melalui titik (-3,4) dan (5,2)
2.tentukan persamaan garis yang melalui titik p(-4,-2) dan (6,3)
Nomor 1 dan 2 menggunakan rumus y-y1/y2-y1 = x- x1/x2-x1

2 Jawaban

  • 1. y-4/2-4 = x-(-3)/5-(-3)
    y-4/-2 = x+4/8
    kali silang 
    8y - 32 = -2x -6
    8y= -2x -6 + 32
    8y= -2x + 26 : 8
    y= -4x + 3 1/4

    2. y - (-2)/ 3 -(-2) = x - (-4)/ 5-(-4)

    y+4/ 5 = x + 4 / 9
    kali silang 
    9(y+4) = 5(x+4)
    9y + 36 = 5x + 20
    9y=5x +20 -36 
    9y= 5x -10 :9
    y= dibagi sembilan aja
  • 1.
    [tex] \frac{y-y1}{y2-y1} [/tex] = [tex] \frac{x-x1}{x2-x1} [/tex]

    [tex] \frac{y-4}{4-2} = \frac{x-(-3)}{-3-5} [/tex]

    [tex] \frac{y-4}{2} = \frac{x + 3}{-8} [/tex]

    -8y - 32 = 2x + 6
    -8y - 2x = 32 + 6
    -8y - 2x = 38

    2.
    [tex] \frac{y-y1}{y2-y1} [/tex] = [tex] \frac{x-x1}{x2-x1} [/tex]

    [tex] \frac{y-(-2)}{3 - (-2)} = \frac{x- (-4)}{6 - (-4)} [/tex]

    [tex] \frac{y + 2}{3 + 2} = \frac{x+4}{6+4} [/tex]

    [tex] \frac{y + 2}{5} = \frac{x+4}{10} [/tex]

    10y + 20 = 5x + 20
    10y - 5x = 20 + 20
    10y - 5x = 40

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