Matematika

Pertanyaan

bentuk sederhana dari 4 akar 3 - akar 12 + akar 27 =

2 Jawaban


  • [tex] \sqrt[3]{4 } - \sqrt{12 } + \sqrt{27} \\ = \sqrt[3]{4} - 2 \sqrt{3} + 3 \sqrt{3} \\ = \sqrt[3]{4} + \sqrt{3} [/tex]
  • 4 akar 3 - akar 12 + akar 27
    =
    [tex]4 \sqrt{3}- \sqrt{12}+ \sqrt{27} \\ = 4 \sqrt{3}- \sqrt{4.3}+ \sqrt{9.3} \\ = 4 \sqrt{3}-2 \sqrt{3}+3 \sqrt{3} \\ (4-2+3) \sqrt{3} \\ 5\sqrt{3}[/tex]

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