jawabnya yah please Jum'at berkah loh :v

[tex]g(x) = {ax}^{2} + b \\ g(2) = a( {2}^{2}) + b \\ - 1= 4a +b \\ g( - 4) = a( { - 4}^{2} ) + b \\ 5 = 16a + b[/tex]

eliminasi dari g(2) dan g(-4)

[tex] - 1 = 4a + b \\ 5 = 16a + b \\ - - - - - - \: \: - (dikurangin) \\ - 6 = - 12a \\ a = \frac{6}{12} = \frac{1}{2} [/tex]

subtitusi a=1/2 ke g(2)

[tex] - 1 = 4a + b \\ - 1 = 4( \frac{1}{2} ) + b \\ - 1 = 2 + b \\ b = - 1 - 2 = - 3[/tex]

[tex]g(x) = \frac{1}{2} {x}^{2} - 3 [/tex]

[tex]g( - 1) + 2 \\ = \frac{1}{2} ( { - 1}^{2} ) - 3 + 2 \\ = \frac{1}{2}(1) - 3 + 2 \\ = \frac{1}{2} - 3 + 2 \\ = - \frac{1}{2} [/tex]

jawabannya A

semoga membantu ^^