tentukan penyelesaian sistem persamaan x-y+1=0 x²+y²=25

[tex]x - y + 1 = 0 \\ x = y - 1[/tex]
masukkan ke pers. 2
[tex] {y - 1}^{2} + {y}^{2} = 25 \\ {y}^{2} - 2y + 1 + {y}^{2} = 25 \\ {2y}^{2} - 2y + 1 = 25 \\ {2y}^{2} - 2y = 24 \\ 2( {y}^{2} - y) = 24 \\ {y}^{2} - y = 12 \\ {y}^{2} - y - 12 = 0[/tex]
(y-4)(y+3)
y = 4
y = -3

x bila y = 4
x = 4-1 =3

x bila y = -3
× = -3 -1 = -4

HP {(3,4),(-4,13)}

mohon dijadikan brainliest answer. terimakasih.