2x-y+z=12 x+2y+z=5 3x-y+2z=19
Matematika
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Pertanyaan
2x-y+z=12
x+2y+z=5
3x-y+2z=19
x+2y+z=5
3x-y+2z=19
2 Jawaban
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1. Jawaban Arkan5283
2x - y + z = 12
x + 2y + z = 5
3x - y + 2z = 19
2x - y + z = 12
z = 12 - 2x + y
x + 2y + z = 5
x + 2y + 12 - 2x + y = 5
- x + 3y = 5 - 12
- x + 3y = - 7
3x - y + 2z = 19
3x - y + 2(12 - 2x + y) = 19
3x - y + 24 - 4x + 2y = 19
- x + y = 19 - 24
- x + y = - 5
(- x + 3y = - 7) × 1
(- x + y = - 5) × 3
- x + 3y = - 7
- 3x + 3y = - 15
___________ _
2x = 8
x = 8/2
x = 4
- x + y = - 5
- 4 + y = - 5
y = - 5 + 4
y = - 1
z = 12 - 2x + y
z = 12 - 2(4) + (- 1)
z = 12 - 8 - 1
z = 3
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