1. 2x² - 3x -5 ≥ 0 2. (x² + 8x + 12) (x² + 6x + 8) ≤ 0
Matematika
NurYuniati
Pertanyaan
1. 2x² - 3x -5 ≥ 0
2. (x² + 8x + 12) (x² + 6x + 8) ≤ 0
2. (x² + 8x + 12) (x² + 6x + 8) ≤ 0
1 Jawaban
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1. Jawaban SadonoSukirno
2x² - 3x - 5 ≥ 0
(2x - 5)(x + 1) ≥ 0
x ≤ -1 atau x ≥ 5/2
(x² + 8x + 12)(x² + 6x + 8) ≤ 0
(x + 2)(x + 6)(x + 4)(x + 2) ≤ 0
+ + + - - - - + + + + + + +
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`````` -6 ````` -4 ````` -2
-6 ≤ x ≤ -4