Matematika

Pertanyaan

1. 2x² - 3x -5 ≥ 0
2. (x² + 8x + 12) (x² + 6x + 8) ≤ 0

1 Jawaban

  • 2x² - 3x - 5 ≥ 0
    (2x - 5)(x + 1) ≥ 0
    x ≤ -1 atau x ≥ 5/2

    (x² + 8x + 12)(x² + 6x + 8) ≤ 0
    (x + 2)(x + 6)(x + 4)(x + 2) ≤ 0
    + + + - - - - + + + + + + +
    ------•-------•-------•--------
    `````` -6 ````` -4 ````` -2
    -6 ≤ x ≤ -4

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