Matematika

Pertanyaan

tolong banget ya please dibantu
pleaseee
tolong banget ya please dibantu pleaseee

2 Jawaban

  • 2)

    x² + 6x – 16 = (x–2) (x+8)
    x= 2 atau x= –8
    12x² + 10x – 2 = (6x–1) (2x+2)
    x= ¹/6 atau x= –1
  • 1.)
    Bentuk umum fungsi linear : f(x) = ax + b
    f(8) = 8a + b
    22 = 8a + b ... (i)

    f(5) = 5a + b
    13 = 5a + b ... (ii)

    Eliminasi persamaan (i) dan (ii)

    8a + b = 22
    5a + b = 13
    –––––––– (–)
    3a = 9
    a = 3

    Subtitusi nilai a ke persamaan (ii)
    13 = 5(3) + b
    b = 13 - 15
    b = -2

    a. Rumus fungsi tersebut : f(x) = 3x - 2

    _______________________

    b. f(2) = 3(2) - 2
    = 6 - 2 = 4

    f(-2) = 3(-2) - 2
    = -6 - 2 = -8

    -> f(2) + f(-2) = 4 - 8
    = -4

    _______________________

    2.)
    a. x² + 6x - 16
    = x² - 2x + 8x - 16
    = x(x - 2) + 8(x - 2)
    = (x + 8)(x - 2)

    ________________________

    b. 12x² + 10x - 2
    = 2[6x² + 5x - 1]
    = 2[6x² + 6x - x - 1]
    = 2[6x(x + 1) - 1(x + 1)]
    = 2(6x - 1)(x + 1)