Matematika

Pertanyaan

tentukan himpunan penyelesaian dari SPLTV berikut dengan metode eliminasi
a.) 2x - y = 1
2x + 3y = 5

b.) 7x -3y = 17
3x + 5y = 1

tentukan himpunan penyelesaian dari SPLTV berikut dengan metode subtitusi
3x - 2y +4z = 10
2x + 3y - 6z = -2
4x - 2y + 5z = 14

1 Jawaban

  • 1a)
    2x - ....y = 1
    2x + 3y = 5
    ----------------- -
    -4y = -4
    y = -4/-4
    y = 1

    2x - y = 1 (×3)
    2x + 3y = 5 (×1)

    6x - 3y = 3
    2x + 3y = 5
    ----------------- +
    8x = 8
    x = 8/8
    x = 1

    Jadi HPnya adalah {1 , 1}


    b)
    7x - 3y = 17 (×3)
    3x + 5y = 1 (×7)

    21x - ...9y = 51
    21x + 35y = ..7
    ---------------------- -
    -44y = 44
    y = 44/-44
    y = -1

    7x - 3y = 17 (×5)
    3x + 5y = 1 (×3)

    35x - 15y = 85
    ..9x + 15y = ..3
    ---------------------- +
    44x = 88
    x = 88/44
    x = 2

    Jadi HPnya adalah {2 , -1}


    2)
    3x - 2y + 4z = 10
    4z = 10 - 3x + 2y
    z = (10 - 3x + 2y)/4

    4x - 2y + 5z = 14
    4x - 2y + 5(10 - 3x + 2y)/4 = 14
    16x/4 - 8y/4 + (50 - 15x + 10y)/4 = 14
    (16x - 8y + 50 - 15x + 10y)/4 = 14
    x + 2y + 50 = 14 × 4
    x + 2y = 56 - 50
    x + 2y = 6 (pers. I)

    2x + 3y - 6z = -2
    6z = 2x + 3y + 2
    z = (2x + 3y + 2)/6

    4x - 2y + 5z = 14
    4x - 2y + 5(2x + 3y + 2)/6 = 14
    24x/6 - 12y/6 + (10x + 15y + 10)/6 = 14
    (24x - 12y + 10x + 15y + 10)/6 = 14
    34x + 3y + 10 = 14 × 6
    34x + 3y = 84 - 10
    34x + 3y = 74 (pers. II)

    x + 2y = 6
    x = 6 - 2y

    34x + 3y = 74
    34(6 - 2y) + 3y = 74
    204 - 68y + 3y = 74
    -65y = 74 - 204
    -65y = -130
    y = -130/-65
    y = 2

    x = 6 - 2y
    x = 6 - 2(2)
    x = 6 - 4
    x = 2

    3x - 2y + 4z = 10
    3(2) - 2(2) + 4z = 10
    6 - 4 + 4z = 10
    2 + 4z = 10
    4z = 10 - 2
    4z = 8
    z = 8/4
    z = 2

    Jadi HPnya adalah {2 , 2 , 2}

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