Matematika

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1 Jawaban

  • Kelas 8 Matematika
    Bab Teorema Pythagoras

    PR = PQ + QR
    PR = 11 + 9
    PR = 20 cm

    PS = √(PR² - RS²)
    PS = √(20² - 12²)
    PS = √(400 - 144)
    PS = √(256)
    PS = 16 cm

    QT/PS = QR/RS
    QT/16 = 9/12
    QT = 16 . 9/12
    QT = 12 cm

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